Solutions Revision Guide for NEET Chemistry
Solutions deals with concentration terms, vapour pressure and colligative properties. Many exam questions are short numericals where correct units and interpretation are more important than lengthy calculation.
For NEET Chemistry, revise mole fraction, molarity, molality, Raoult law, ideal and non-ideal behaviour, elevation of boiling point, depression of freezing point and osmotic pressure.
Important Topics
- Concentration terms
- Raoult law
- Ideal and non-ideal solutions
- Colligative properties
- van’t Hoff factor
- Osmotic pressure
Important Formulae & Relationships
Molarity M = moles of solute / volume of solution (L)Molality m = moles of solute / mass of solvent (kg)ΔTb = iKb mΔTf = iKf mπ = iCRT
Use formulas only after checking the required units, sign convention and assumptions for the question.
Top 20 Solutions MCQs with Answers
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NEET Chemistry · Solutions · Very Hard
1. Raoult's law for a volatile component A is:
- A. pA = pA°/xA
- B. pA = xB pA°
- C. pA = pA° − xA
- D. pA = xA pA°
Answer: DExplanation: The partial vapour pressure of component A equals its mole fraction in solution multiplied by vapour pressure of pure A.
NEET Chemistry · Solutions · Very Hard
2. Consider the statements: (I) Osmotic pressure is useful for determining molar masses of macromolecules. (II) Molality is temperature-independent. (III) Positive deviation means stronger A–B interactions. (IV) Colligative properties depend on particle number. Which are correct?
- A. I, II, III and IV
- B. I, II and IV only
- C. I and III only
- D. II and III only
Answer: BExplanation: I, II and IV are correct. Positive deviation results from weaker, not stronger, A–B interactions.
NEET Chemistry · Solutions · Very Hard
3. The total vapour pressure of an ideal binary volatile solution is:
- A. pA°pB°
- B. xA pA° + xB pB°
- C. pA° + pB°
- D. xA + xB
Answer: BExplanation: Dalton's law and Raoult's law give Ptotal = pA + pB = xA pA° + xB pB°.
NEET Chemistry · Solutions · Very Hard
4. A solution shows positive deviation from Raoult's law when:
- A. A–B attractions are stronger
- B. ΔHmix is highly negative
- C. Vapour pressure is lower than ideal
- D. A–B attractions are weaker than A–A and B–B attractions
Answer: DExplanation: Weaker unlike interactions allow molecules to escape more readily, raising vapour pressure above the ideal value.
NEET Chemistry · Solutions · Very Hard
5. A solution showing negative deviation from Raoult's law generally has:
- A. Higher vapour pressure than ideal
- B. Stronger A–B interactions
- C. Weaker A–B interactions
- D. Positive ΔHmix only
Answer: BExplanation: Stronger unlike interactions reduce escaping tendency, giving lower vapour pressure and negative deviation.
NEET Chemistry · Solutions · Very Hard
6. A minimum-boiling azeotrope is generally formed by solutions showing:
- A. Only nonvolatile solutes
- B. Positive deviation from Raoult's law
- C. Negative deviation
- D. No deviation
Answer: BExplanation: Positive deviation raises vapour pressure and lowers boiling point, producing a minimum-boiling azeotrope.
NEET Chemistry · Solutions · Very Hard
7. A maximum-boiling azeotrope is generally formed by solutions showing:
- A. Positive deviation
- B. Ideal behaviour
- C. Complete immiscibility
- D. Negative deviation from Raoult's law
Answer: DExplanation: Negative deviation lowers vapour pressure and raises boiling point, producing a maximum-boiling azeotrope.
NEET Chemistry · Solutions · Very Hard
8. Elevation in boiling point is given by:
- A. ΔTb = Kf m
- B. ΔTb = m/Kb
- C. ΔTb = Kb/M
- D. ΔTb = Kb m
Answer: DExplanation: For dilute solutions, boiling-point elevation equals ebullioscopic constant times molality.
NEET Chemistry · Solutions · Very Hard
9. Depression in freezing point is given by:
- A. ΔTf = m/Kf
- B. ΔTf = Kf m
- C. ΔTf = Kb m
- D. ΔTf = Kf/M
Answer: BExplanation: For dilute solutions, freezing-point depression equals cryoscopic constant times molality.
NEET Chemistry · Solutions · Very Hard
10. Reverse osmosis occurs when external pressure applied on the solution side is:
- A. Zero
- B. Greater than osmotic pressure
- C. Less than osmotic pressure
- D. Equal to vapour pressure only
Answer: BExplanation: Applying pressure greater than osmotic pressure forces solvent from solution through the semipermeable membrane toward pure solvent.
NEET Chemistry · Solutions · Very Hard
11. A solution contains 0.5 mol solute and 2.0 kg solvent. Its molality is:
- A. 1.0 m
- B. 2.5 m
- C. 4.0 m
- D. 0.25 m
Answer: DExplanation: Molality = moles of solute / kilograms of solvent = 0.5/2.0 = 0.25 m.
NEET Chemistry · Solutions · Very Hard
12. The mole fraction of a component in a binary solution is:
- A. Mass divided by solution volume
- B. Moles of that component divided by total moles
- C. Mass of that component divided by total mass
- D. Moles divided by solvent mass in kg
Answer: BExplanation: Mole fraction is defined as the ratio of moles of one component to total moles of all components.
NEET Chemistry · Solutions · Very Hard
13. For an ideal solution, the enthalpy of mixing is:
- A. Positive
- B. Negative
- C. Infinite
- D. Zero
Answer: DExplanation: In an ideal solution, A–B interactions are comparable to A–A and B–B interactions, so ΔHmix = 0.
NEET Chemistry · Solutions · Very Hard
14. For an ideal solution, the volume change on mixing is:
- A. Equal to molar volume
- B. Zero
- C. Positive
- D. Negative
Answer: BExplanation: Ideal solutions obey ΔVmix = 0 because intermolecular packing is not significantly altered on mixing.
NEET Chemistry · Solutions · Very Hard
15. Henry's law is commonly written as:
- A. p = x + KH
- B. p = KH x
- C. p = x/KH
- D. p = KH/x
Answer: BExplanation: Henry's law states that the partial pressure of a gas is proportional to its mole fraction in solution: p = KHx.
NEET Chemistry · Solutions · Very Hard
16. The relative lowering of vapour pressure for a dilute solution of a nonvolatile solute equals approximately:
- A. Molarity
- B. Mole fraction of solute
- C. Mole fraction of solvent
- D. Molality
Answer: BExplanation: For dilute solutions, (p°−p)/p° = xsolute.
NEET Chemistry · Solutions · Very Hard
17. The osmotic pressure of a dilute solution is:
- A. π = C/RT
- B. π = RT/C
- C. π = Kf m
- D. π = CRT
Answer: DExplanation: The van't Hoff equation for dilute solutions is π = CRT.
NEET Chemistry · Solutions · Very Hard
18. The van't Hoff factor i is greater than one when the solute:
- A. Associates
- B. Does not change particle count
- C. Is nonvolatile only
- D. Dissociates
Answer: DExplanation: Dissociation increases the number of solute particles, so observed colligative effect and i exceed one.
NEET Chemistry · Solutions · Very Hard
19. For complete dissociation of CaCl2 in a very dilute solution, the ideal van't Hoff factor is:
Answer: DExplanation: CaCl2 gives one Ca2+ and two Cl− ions, producing three particles per formula unit.
NEET Chemistry · Solutions · Very Hard
20. Which concentration term is independent of temperature?
- A. Volume percentage
- B. Molality
- C. Molarity
- D. Normality
Answer: BExplanation: Molality depends on moles of solute per kilogram of solvent, both mass-based quantities, so it is independent of temperature.
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