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Hydrocarbons WBCHSE Class 11 MCQ & Practice Questions

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Hydrocarbons Revision Guide for WBCHSE Class 11 Chemistry

Hydrocarbons is part of WBCHSE Class 11 Chemistry preparation. A strong revision plan should combine concept review with exam-style questions so that definitions, relationships, calculations and exceptions are recalled accurately.

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What to practise in Hydrocarbons

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Top 20 Hydrocarbons MCQs with Answers

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WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

1. The general formula of an acyclic saturated hydrocarbon is:

  • A. CnH2n-2
  • B. CnHn
  • C. CnH2n+2
  • D. CnH2n
Answer: C
Explanation: Open-chain alkanes follow CnH2n+2.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

2. The hybridisation of carbon in methane is:

  • A. dsp2
  • B. sp3
  • C. sp2
  • D. sp
Answer: B
Explanation: Methane has four equivalent sigma bonds and tetrahedral sp3 carbon.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

3. The approximate H-C-H angle in methane is:

  • A. 109.5°
  • B. 120°
  • C. 180°
  • D. 90°
Answer: A
Explanation: Tetrahedral geometry gives an angle of about 109.5°.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

4. The characteristic reaction of alkanes with halogens under UV light is:

  • A. Electrophilic addition
  • B. Nucleophilic addition
  • C. Hydrolysis
  • D. Free-radical substitution
Answer: D
Explanation: Alkane halogenation proceeds through a radical chain mechanism.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

5. The initiation step in chlorination of methane involves:

  • A. Formation of carbocation
  • B. Formation of carbanion
  • C. Homolytic cleavage of Cl2
  • D. Heterolytic cleavage of CH4
Answer: C
Explanation: Light causes Cl-Cl homolysis to chlorine radicals.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

6. Wurtz reaction is useful for preparing:

  • A. Aldehydes
  • B. Higher alkanes
  • C. Alkenes only
  • D. Alcohols
Answer: B
Explanation: Alkyl halides couple with sodium in dry ether to form higher alkanes.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

7. Decarboxylation of sodium carboxylate with soda lime gives an alkane having:

  • A. One carbon less
  • B. One carbon more
  • C. Same number of carbons always
  • D. Two carbons more
Answer: A
Explanation: Loss of the carboxyl carbon gives an alkane with one fewer carbon.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

8. Kolbe electrolysis of a carboxylate salt can produce:

  • A. Only an alcohol
  • B. Only an alkene
  • C. A ketone only
  • D. An alkane by radical coupling
Answer: D
Explanation: Anodic decarboxylation generates radicals that couple.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

9. The most stable conformation of ethane is:

  • A. Planar square
  • B. Boat
  • C. Staggered
  • D. Eclipsed
Answer: C
Explanation: Staggering minimises torsional strain.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

10. The eclipsed conformation of ethane is less stable because of:

  • A. Ionic repulsion
  • B. Torsional strain
  • C. Aromaticity
  • D. Hydrogen bonding
Answer: B
Explanation: Bonding electron pairs are aligned, increasing torsional repulsion.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

11. The general formula of an acyclic monoalkene is:

  • A. CnH2n
  • B. CnH2n+2
  • C. CnH2n-2
  • D. CnHn
Answer: A
Explanation: One C=C reduces hydrogen count by two relative to alkane.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

12. Carbon atoms of a C=C bond are generally:

  • A. sp3 hybridised
  • B. sp hybridised
  • C. d2sp3 hybridised
  • D. sp2 hybridised
Answer: D
Explanation: Each alkene carbon uses sp2 orbitals and one unhybridised p orbital.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

13. The C=C bond contains:

  • A. Two pi bonds
  • B. One pi bond only
  • C. One sigma and one pi bond
  • D. Two sigma bonds
Answer: C
Explanation: Double bonds consist of one sigma and one pi component.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

14. Restricted rotation about C=C is responsible for:

  • A. Tautomerism only
  • B. Geometrical isomerism
  • C. Chain isomerism only
  • D. Metamerism
Answer: B
Explanation: Rotation would require disruption of pi overlap.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

15. Ethene decolourises bromine solution because it undergoes:

  • A. Addition
  • B. Substitution only
  • C. Elimination
  • D. Condensation
Answer: A
Explanation: Bromine adds across the carbon-carbon double bond.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

16. Hydrogenation of an alkene produces:

  • A. An alkyne
  • B. An aromatic compound
  • C. A carboxylic acid
  • D. An alkane
Answer: D
Explanation: H2 adds across C=C, saturating it.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

17. Markovnikov's rule predicts addition of HX to an unsymmetrical alkene such that H adds mainly to carbon with:

  • A. Higher atomic mass
  • B. Aromatic character
  • C. More hydrogens already attached
  • D. Fewer hydrogens always
Answer: C
Explanation: The usual orientation corresponds to formation of the more stable carbocation intermediate.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

18. Peroxide effect is classically observed in addition of:

  • A. HF
  • B. HBr
  • C. HCl
  • D. HI
Answer: B
Explanation: In presence of peroxides HBr can add by a radical anti-Markovnikov pathway.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

19. Ozonolysis of an alkene is useful for locating:

  • A. Position of the double bond
  • B. Only carbon-carbon single bonds
  • C. Halogen atoms
  • D. Hydrogen bonds
Answer: A
Explanation: Cleavage products reveal the carbon skeleton around C=C.

WBCHSE Class 11 Chemistry · Hydrocarbons · Very Hard

20. Cold dilute alkaline KMnO4 converts an alkene mainly into:

  • A. Alkane
  • B. Alkyne
  • C. Aromatic ring
  • D. Vicinal diol
Answer: D
Explanation: Baeyer's reagent oxidises C=C to a glycol under mild conditions.

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Hydrocarbons Practice Tests

Hydrocarbons Frequently Asked Questions

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