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p-Block Elements 1 WBJEE MCQ & Practice Questions

Practice p-Block Elements 1 MCQs for WBJEE Chemistry with answers, explanations, chapter revision and related ChemNexa mock tests.

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p-Block Elements 1 Revision Guide for WBJEE Chemistry

p-Block Elements covers periodic trends, structures, oxidation states and important compounds of groups 13 to 18 depending on the syllabus. Questions often test trends together with exceptions.

For WBJEE Chemistry, organise revision group-wise and compare oxidation states, acidic or basic character, anomalous behaviour, structures and important reactions.

Important Topics

  • Group-wise periodic trends
  • Anomalous behaviour of first elements
  • Oxidation states and inert-pair effect
  • Structures of important compounds
  • Acidic and basic character
  • Important reactions and uses

Revision Tip

Create a one-page summary of trends, structures, reactions, exceptions and key terminology for p-Block Elements 1, then test recall with mixed MCQs.

What to practise in p-Block Elements 1

Concept Revision

Revise definitions, principles, equations, trends and core ideas from p-Block Elements 1 before attempting MCQs.

Exam-style MCQs

Use chapter-focused multiple-choice practice to improve accuracy, recall and application for WBJEE Chemistry.

Performance Practice

Attempt ChemNexa tests, review results and return to weak areas for another round of targeted revision.

Top 20 p-Block Elements 1 MCQs with Answers

These public questions are selected from the exact p-Block Elements 1 chapter, screened for topic relevance and deduplicated so repeated versions of the same MCQ are not shown publicly. Use them for quick revision, then sign in to attempt the complete test experience with more questions, results and performance review.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

1. The shape of ClF3 is:

  • A. Linear
  • B. Tetrahedral
  • C. T-shaped
  • D. Trigonal planar
Answer: C
Explanation: ClF3 has five electron pairs around Cl, with two lone pairs in equatorial sites.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

2. The shape of IF7 is:

  • A. Trigonal bipyramidal
  • B. Pentagonal bipyramidal
  • C. Octahedral
  • D. Square pyramidal
Answer: B
Explanation: Seven bond pairs around iodine give pentagonal bipyramidal geometry.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

3. The first noble-gas compound was prepared using:

  • A. Xe and PtF6
  • B. He and F2
  • C. Ne and O2
  • D. Ar and Cl2
Answer: A
Explanation: Bartlett's work with xenon and platinum hexafluoride initiated noble-gas chemistry.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

4. Non-metal chemistry concept check: The shape of ClF3 is:

  • A. T-shaped
  • B. Trigonal planar
  • C. Linear
  • D. Tetrahedral
Answer: A
Explanation: ClF3 has five electron pairs around Cl, with two lone pairs in equatorial sites.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

5. Non-metal chemistry concept check: The shape of IF7 is:

  • A. Octahedral
  • B. Square pyramidal
  • C. Trigonal bipyramidal
  • D. Pentagonal bipyramidal
Answer: D
Explanation: Seven bond pairs around iodine give pentagonal bipyramidal geometry.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

6. Non-metal chemistry concept check: The first noble-gas compound was prepared using:

  • A. Ne and O2
  • B. Ar and Cl2
  • C. Xe and PtF6
  • D. He and F2
Answer: C
Explanation: Bartlett's work with xenon and platinum hexafluoride initiated noble-gas chemistry.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

7. WBJEE advanced: The shape of ClF3 is:

  • A. Linear
  • B. Tetrahedral
  • C. T-shaped
  • D. Trigonal planar
Answer: C
Explanation: ClF3 has five electron pairs around Cl, with two lone pairs in equatorial sites.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

8. WBJEE advanced: The shape of IF7 is:

  • A. Trigonal bipyramidal
  • B. Pentagonal bipyramidal
  • C. Octahedral
  • D. Square pyramidal
Answer: B
Explanation: Seven bond pairs around iodine give pentagonal bipyramidal geometry.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

9. WBJEE advanced: The first noble-gas compound was prepared using:

  • A. Xe and PtF6
  • B. He and F2
  • C. Ne and O2
  • D. Ar and Cl2
Answer: A
Explanation: Bartlett's work with xenon and platinum hexafluoride initiated noble-gas chemistry.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

10. Among halogens, the strongest oxidising agent is:

  • A. I2
  • B. F2
  • C. Cl2
  • D. Br2
Answer: B
Explanation: F2 has the greatest tendency to be reduced.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

11. The reducing power of halide ions generally follows:

  • A. I- > Br- > Cl- > F-
  • B. F- > Cl- > Br- > I-
  • C. Cl- > F- > I- > Br-
  • D. Br- > I- > F- > Cl-
Answer: A
Explanation: I- is oxidised most readily, whereas F- is most difficult to oxidise.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

12. The shape of XeF2 is:

  • A. Linear
  • B. Bent
  • C. Trigonal planar
  • D. T-shaped
Answer: A
Explanation: Three equatorial lone pairs in trigonal-bipyramidal electron geometry leave axial F atoms.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

13. The shape of XeF4 is:

  • A. Tetrahedral
  • B. Square pyramidal
  • C. Trigonal planar
  • D. Square planar
Answer: D
Explanation: XeF4 has six electron pairs with two opposite lone pairs.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

14. The shape of XeF6 is commonly described as:

  • A. Linear
  • B. Trigonal planar
  • C. Distorted octahedral
  • D. Perfect tetrahedral
Answer: C
Explanation: A lone pair causes distortion from ideal octahedral geometry.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

15. Noble gases are chemically unreactive mainly because they have:

  • A. One valence electron
  • B. Stable closed-shell electronic configurations
  • C. Very low ionisation enthalpies
  • D. Very high electron affinities
Answer: B
Explanation: Their filled valence shells are exceptionally stable.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

16. H3PO2 is:

  • A. Dibasic
  • B. Tribasic
  • C. Tetrabasic
  • D. Monobasic
Answer: D
Explanation: Only one hydrogen is bonded to oxygen and is ionisable.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

17. H3PO3 is:

  • A. Tribasic
  • B. Tetrabasic
  • C. Dibasic
  • D. Monobasic
Answer: C
Explanation: Two P-OH hydrogens are ionisable; one P-H hydrogen is not.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

18. H3PO4 is:

  • A. Nonbasic
  • B. Tribasic
  • C. Dibasic
  • D. Monobasic
Answer: B
Explanation: It has three ionisable P-OH hydrogens.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

19. The reducing character of H3PO2 is associated with:

  • A. P-H bonds
  • B. P-O-P bonds only
  • C. P=O bond only
  • D. O-H bonds only
Answer: A
Explanation: P-H bonds enable reducing behaviour.

WBJEE Chemistry · p-Block Elements 1 · Very Very Hard

20. SO2 commonly acts as a:

  • A. Reducing agent
  • B. Strong oxidising agent only
  • C. Noble gas
  • D. Metal
Answer: A
Explanation: Sulfur in +4 state can be oxidised to +6.

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p-Block Elements 1 Practice Tests

p-Block Elements 1 Frequently Asked Questions

How should I memorise p-Block Chemistry?

Use comparison tables by group and focus on trends, important exceptions, structures and reactions instead of memorising disconnected facts.

Why are exceptions important in p-Block questions?

Small size, high electronegativity, absence of d orbitals in second-period elements and inert-pair effects create frequently tested deviations from simple trends.

What is a good revision method for p-Block?

Revise one group at a time, write the common oxidation states and key compounds, then immediately solve targeted MCQs.

Continue with another chapter to build connected concepts and strengthen your overall Chemistry preparation.

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