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Chemical Bonding and Molecular Structure JEE Main MCQ & Practice Questions

Practice Chemical Bonding and Molecular Structure MCQs for JEE Main Chemistry with answers, explanations, chapter revision and related ChemNexa mock tests.

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Chemical Bonding and Molecular Structure Revision Guide for JEE Main Chemistry

Chemical Bonding and Molecular Structure explains why atoms combine and how bonding controls molecular shape, polarity and properties. It is a high-connectivity chapter because its ideas reappear throughout inorganic and organic chemistry.

For JEE Main Chemistry, combine Lewis structures with VSEPR, hybridisation, valence bond ideas and molecular orbital theory. Practise predicting geometry and magnetic behaviour rather than memorising examples without reasoning.

Important Topics

  • Lewis structures and formal charge
  • VSEPR theory and molecular geometry
  • Hybridisation
  • Bond parameters and polarity
  • Hydrogen bonding
  • Molecular orbital theory

Important Formulae & Relationships

  • Formal charge = valence e− − nonbonding e− − 1/2(bonding e−)
  • Bond order (MOT) = 1/2(Nb − Na)
  • Dipole moment μ = q × r

Use formulas only after checking the required units, sign convention and assumptions for the question.

What to practise in Chemical Bonding and Molecular Structure

Concept Revision

Revise definitions, principles, equations, trends and core ideas from Chemical Bonding and Molecular Structure before attempting MCQs.

Exam-style MCQs

Use chapter-focused multiple-choice practice to improve accuracy, recall and application for JEE Main Chemistry.

Performance Practice

Attempt ChemNexa tests, review results and return to weak areas for another round of targeted revision.

Top 20 Chemical Bonding and Molecular Structure MCQs with Answers

These public questions are selected from the exact Chemical Bonding and Molecular Structure chapter, screened for topic relevance and deduplicated so repeated versions of the same MCQ are not shown publicly. Use them for quick revision, then sign in to attempt the complete test experience with more questions, results and performance review.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

1. The hybridisation of each carbon in ethene is

  • A. sp2
  • B. sp3
  • C. sp
  • D. d2sp3
Answer: A
Explanation: Each carbon forms three sigma bonds and one pi bond.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

2. The hybridisation of each carbon in ethyne is

  • A. sp2
  • B. sp3
  • C. dsp2
  • D. sp
Answer: D
Explanation: Each carbon forms two sigma bonds and two pi bonds.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

3. The shape of BeCl2 in the gaseous state is

  • A. Trigonal planar
  • B. Tetrahedral
  • C. Linear
  • D. Bent
Answer: C
Explanation: Two bond pairs around Be give sp hybridisation and linear geometry.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

4. The hybridisation of carbon in methane is

  • A. dsp2
  • B. sp3
  • C. sp2
  • D. sp
Answer: B
Explanation: Four equivalent sigma bonds require four sp3 hybrid orbitals.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

5. A carbon-carbon triple bond contains

  • A. Three pi bonds
  • B. One sigma and two pi bonds
  • C. Three sigma bonds
  • D. Two sigma and one pi bond
Answer: B
Explanation: A triple bond has one sigma bond and two mutually perpendicular pi bonds.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

6. According to molecular orbital theory, bond order is

  • A. Nb+Na
  • B. Nb/Na
  • C. (Nb−Na)/2
  • D. (Na−Nb)/2
Answer: C
Explanation: Bond order equals half the difference between bonding and antibonding electrons.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

7. The bond order of O2 is

  • A. 3
  • B. 2
  • C. 1
  • D. 2.5
Answer: B
Explanation: O2 has eight bonding and four antibonding valence electrons, giving bond order 2.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

8. An ionic bond is formed primarily by

  • A. Overlap of half-filled orbitals only
  • B. Hydrogen bonding
  • C. Electrostatic attraction between oppositely charged ions
  • D. Equal sharing of electrons
Answer: C
Explanation: Ionic bonding results from electron transfer followed by electrostatic attraction.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

9. According to Fajans' rule, covalent character increases with

  • A. Small highly charged cation and large polarizable anion
  • B. Large monovalent cation and small anion
  • C. Low cation charge only
  • D. Zero polarisation
Answer: A
Explanation: High polarising power and high polarizability favour covalent character.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

10. The formal charge on an atom is calculated as

  • A. Bonding electrons − valence electrons
  • B. Nonbonding electrons only
  • C. Oxidation state plus valency
  • D. Valence electrons − nonbonding electrons − half bonding electrons
Answer: D
Explanation: Formal charge assigns half of shared electrons to each bonded atom.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

11. The shape of BF3 is

  • A. Tetrahedral
  • B. Trigonal planar
  • C. Trigonal pyramidal
  • D. T-shaped
Answer: B
Explanation: Three bond pairs and no lone pair on B give trigonal planar geometry.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

12. The shape of NH3 is

  • A. Trigonal pyramidal
  • B. Trigonal planar
  • C. Tetrahedral
  • D. Bent
Answer: A
Explanation: Three bonds and one lone pair around N give a trigonal pyramidal shape.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

13. The shape of H2O is

  • A. Linear
  • B. Trigonal planar
  • C. Tetrahedral
  • D. Bent
Answer: D
Explanation: Two bond pairs and two lone pairs on O produce a bent molecule.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

14. The bond-angle order is

  • A. NH3 > CH4 > H2O
  • B. All are equal
  • C. CH4 > NH3 > H2O
  • D. H2O > NH3 > CH4
Answer: C
Explanation: Lone-pair repulsion compresses bond angles: 109.5° > 107° > 104.5°.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

15. A carbon-carbon double bond contains

  • A. Two pi bonds
  • B. One sigma bond only
  • C. One sigma and one pi bond
  • D. Two sigma bonds
Answer: C
Explanation: A double bond consists of one head-on sigma and one sidewise pi bond.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

16. Which bond is generally strongest?

  • A. C≡C
  • B. C=C
  • C. C−C
  • D. All are equal
Answer: A
Explanation: Bond strength increases with bond order.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

17. Which bond is generally shortest?

  • A. C=C
  • B. C−C
  • C. All are equal
  • D. C≡C
Answer: D
Explanation: Bond length decreases as bond order increases.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

18. The dipole moment of CO2 is zero because

  • A. It has no electrons
  • B. It is ionic
  • C. Its bond dipoles cancel in a linear geometry
  • D. C=O bonds are nonpolar
Answer: C
Explanation: The two equal C=O dipoles point in opposite directions.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

19. NH3 has a nonzero dipole moment because it is

  • A. Square planar
  • B. Trigonal pyramidal
  • C. Trigonal planar
  • D. Linear
Answer: B
Explanation: Its bond dipoles do not cancel in the pyramidal geometry.

JEE Main Chemistry · Chemical Bonding and Molecular Structure · Very Hard

20. Hydrogen bonding is strongest when hydrogen is bonded to

  • A. F, O or N
  • B. Cl, Br or I only
  • C. Carbon only
  • D. Any metal
Answer: A
Explanation: Small, highly electronegative atoms produce strongly polar X−H bonds.

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Chemical Bonding and Molecular Structure Practice Tests

Chemical Bonding and Molecular Structure Frequently Asked Questions

What should I master first in Chemical Bonding?

Start with Lewis structures, electron-pair counting and VSEPR. These make geometry and hybridisation questions much easier.

Why is molecular orbital theory important?

It explains bond order and magnetic behaviour, including cases that simple Lewis structures cannot describe adequately.

How can I avoid geometry mistakes?

Count electron domains around the central atom, distinguish electron-pair geometry from molecular shape, and then account for lone-pair repulsions.

Continue with another chapter to build connected concepts and strengthen your overall Chemistry preparation.

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